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Dual-Dielectric
Coaxial Cable
Question:
Once upon a time,
I had an equation for computing effective dielectric constant for
a coax line with mixed dielectrics. Can anyone supply the equation
and/or reference material?
The Professor Answers.....

When a coaxial
cable is constructed using two concentric dielectrics as shown above,
the wave propagation is no longer purely TEM, as in the single-dielectric
coax, but instead is quasi-TEM. Therefore, in general the characteristic
impedance and effective dielectric constant are functions of frequency.
However, the static Zo and Keff terms can be derived easily, and
they are useful over a fairly wide range of frequencies. The derivation
of these terms is as follows:
In the static
(DC) case, all of the electric flux lines are perpendicular to the
center conductor - dielectric 1, dielectric 1 - dielectric 2, and
dielectric 2 - outer conductor interfaces, as shown:

To calculate
the static capacitance between the inner and outer conductors, imagine
a zero-thickness conducting cylinder placed inside the cable, at
the interface between the two dielectrics. Since all of the electric
field components are already perpendicular to this interface, this
does not violate the boundary conditions of the initial problem.
With this conducting cylinder in place, two capacitance values can
now be calculated: 1) the capacitance (per meter length of cable)
between the inner conductor and the cylinder; and 2) the capacitance
between the cylinder and the outer conductor. The capacitance per
meter of cable between the inner and outer conductors is then the
series combination of the above two capacitance values.

The capacitance
per length of a single-dielectric coaxial cable (dimensions shown
above) is as follows:

Therefore, the
capacitance per meter length between the inner conductor and the
cylinder is:

The capacitance
per meter length between the cylinder and the outer conductor is:

The capacitance per meter length of the cable itself is the series
combination of the above two capacitances:

Leaving out the
algebraic steps, this comes out to:

The effective
dielectric constant of the structure is the ratio of the capacitance
of the structure to the capacitance if the dielectrics were replaced
with a vacuum (or air), i.e.:

where: 
This gives the
following expression for the effective dielectric constant:

With a bit of additional effort, the characteristic impedance can
also be found. For this we need the inductance per meter length,
which is unaffected by the dielectric(s) in the structure. The expression
for the inductance is:

The characteristic
impedance of any transmission line is equal to the square root of
the ratio of the inductance per length to the capacitance per length.
Again leaving out the algebraic steps,

I validated these
expressions using HFSS for the following geometry: r0 = 0.040",
r1 = 0.100", r2 = 0.140", Er1 = 2.0, and Er2 = 5.0. For
those dimensions, the above expressions yield Z0 = 48.65 ,
and Keff = 2.384. HFSS results for the same configuration are as
follows:
| Frequency,GHz
Keff |
Z0,Ohms (P-V) |
Keff |
| 1.0 |
48.62 |
2.384 |
| 2.0 |
48.63 |
2.385 |
| 3.0 |
48.64 |
2.386 |
| 4.0 |
48.65 |
2.387 |
| 5.0 |
48.67 |
2.389 |
| 6.0 |
48.69 |
2.391 |
| 7.0 |
48.71 |
2.393 |
| 8.0 |
48.73 |
2.396 |
| 9.0 |
48.76 |
2.399 |
| 10.0 |
48.79 |
2.403 |
| 11.0 |
48.82 |
2.407 |
| 12.0 |
48.86 |
2.412 |
| 13.0 |
48.89 |
2.417 |
| 14.0 |
48.92 |
2.423 |
| 15.0 |
48.96 |
2.429 |
As seen from
the numbers, the expressions for the static Z0 and Keff are valid
at low frequencies, and for the dimensions used in this example,
the dispersion is mild below 15 GHz. Smaller dimensions and closer
values of Er1 and Er2 would reduce the dispersion further.
I hope you find
this helpful. The derivation of the expressions for Z0 and Keff
in the case in which the division between Er1 and Er2 is angular,
rather than radial, is probably more complicated.
Regards,
The Professor
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