|
Dielectric-loaded
waveguide
Updated November
20, 2007
Click
here to go to our main page on waveguide
Click
here to go to our main page on waveguide loss
New for December 2007!
Rectangular waveguide is most often filled with air, sometimes pressurized
in high-power application. Why would you want to fill it with a
dielectric? One reason is to shrink the dimensions. Sometimes you
might want to load the waveguide with a ferrite material, perhaps
to make a circulator.
While we're waiting for this
page to emerge from the fog, go to the download
area and get the latest waveguide loss spreadsheet, it now includes
the ability to account for dielectric loading!
The waveguide can be partially
loaded, or completely loaded with a dielectric material. For now,
the analysis on this page only considers the fully loaded case.
It's easier to analyze, OK?
For reference, we used Pozar's
Microwave Engineering, which you can find on our book
page. Launch from there into Amazon and order yourself a copy.
Let's start with the easiest
calculation, the wave number at cutoff. Let's also concentrate on
the TE10 mode, which is what 99.99% of time all we care about in
rectangular waveguide.

Now let's consider the wavenumber,
k. In waveguide the wavenumber is reduced below what it would be
for TEM media, especially as you get close to cut-off:




Here's a new page on wave
number.
More to come!
|